Performing arithmetic operations using **switch...case**

### Program:

#include<stdio.h> #include<conio.h> void main() { int n1, n2, ch; clrscr(); printf("Enter the first number : ") ; scanf("%d", &n1) ; printf("\nEnter the second number : ") ; scanf("%d", &n2) ; printf("\n[1] -> Addition ") ; printf("\n[2] -> Subtraction ") ; printf("\n[3] -> Multiplication ") ; printf("\n[4] -> Division ") ; printf("\n\nEnter your choice <1...4> : ") ; scanf("%d", &ch) ; switch(ch) { case 1 : printf("\n%d + %d = %d", n1, n2, n1 + n2) ; break ; case 2 : printf("\n%d - %d = %d", n1, n2, n1 - n2) ; break ; case 3 : printf("\n%d * %d = %d", n1, n2, n1 * n2); break ; case 4 : printf("\n%d / %d = %.2f", n1, n2, (float)n1 / n2); break ; default : printf("\nInvalid choice"); break ; } getch(); }

### Output:

Enter the first number : 10 Enter the second number : 5 [1] -> Addition [2] -> Subtraction [3] -> Multiplication [4] -> Division Enter your choice <1...4> : 3 10 * 5 = 50

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