Program to find

and **LCM **

of the given two numbers**GCD **

### Program:

#include<stdio.h> #include<conio.h> void main() { int n1, n2, prod, gcd, lcm ; clrscr() ; printf("Enter the two numbers : ") ; scanf("%d %d", &n1, &n2) ; prod = n1 * n2 ; while(n1 != n2) { if(n1 > n2) n1 = n1 - n2 ; if(n2 > n1) n2 = n2 - n1 ; } gcd = n1 ; lcm = prod / gcd ; printf("\nThe GCD is : %d", gcd) ; printf("\n\nThe LCM is : %d", lcm); getch() ; }

### Output:

Enter the two numbers : 10 8 The GCD is : 2 The LCM is : 40

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### Comments

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