Program to** change an integer to words**

### Program:

#include<stdio.h> #include<conio.h> void main() { long n, a[10], i, c = 0 ; clrscr() ; printf("Enter a number : ") ; scanf("%ld", &n) ; while(n > 0) { a[c] = n % 10 ; n = n / 10 ; c++; } printf("\n") ; for(i = c - 1 ; i >= 0 ; i--) { switch(a[i]) { case 0 : printf("ZERO ") ; break ; case 1 : printf("ONE ") ; break ; case 2 : printf("TWO ") ; break ; case 3 : printf("THREE ") ; break ; case 4 : printf("FOUR ") ; break ; case 5 : printf("FIVE ") ; break ; case 6 : printf("SIX ") ; break ; case 7 : printf("SEVEN ") ; break ; case 8 : printf("EIGHT ") ; break ; case 9 : printf("NINE ") ; break ; } } getch() ; }

### Output:

Enter a number : 225589 TWO TWO FIVE FIVE EIGHT NINE

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### Comments

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