Find the root of a equation using Newton Raphson
Program:
#include<stdio.h>
#include<conio.h>
#include<math.h>
#define EPS 0.000001
#define MAXIT 20
#define F(x) (x) * (x) * (x)  2 * (x)  5
#define FD(x) 3 * (x) * (x)  2
void main()
{
int count;
float x0, xn, fx, fdx;
clrscr();
printf("Input initial value of x : ");
scanf("%f", &x0);
count = 1;
begin:
fx = F(x0);
fdx = FD(x0);
xn = x0  fx / fdx;
if(fabs((xn  x0) / xn) < EPS)
{
printf("\nRoot = %f", xn);
printf("\n\nNumber of iterations = %d", count);
}
else
{
x0 = xn;
count = count + 1;
if(count < MAXIT)
{
goto begin;
}
else
{
printf("\nSolution does not coverage in %d iterations", MAXIT);
}
}
getch();
}
Output:
Input initial value of x : 0
Root = 2.094552
Number of iterations = 19

CreatedOct 18, 2014

UpdatedDec 31, 2019

Views3,017
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